목차(저압 옥내배전방식)
저압 옥내배전방식
결선도 | 공급전력 전선총량 | 선전류 | 전선단면적 | 전압강하 | 배전손실 | |
---|---|---|---|---|---|---|
단상2선식 | \[P=EI_1\] \[V=2S_1L\] | \[I_1\] \[100[\%]\] | \[S_1\] \[100[\%]\] | \[e_1=2I_1R_1\] \[=2\frac{I_1\rho L}{S_1}\] \[100[\%]\] | \[Q_1=2I^2_1R_1\] \[=2I^2_1\frac{\rho L}{S_1}\] \[100\%\] | |
단상3선식 | \[P=2EI_2\] \[V=3S_2L\] | \[I_2=\frac{I_1}{2}\] \[50[\%]\] | \[S_2=\frac{2}{3} S_1\] \[66.7[\%]\] | \[e_2=I_2R_2\] \[=(\frac{I_1}{2})\frac{\rho L}{S_2}\] \[=(\frac{I_1}{2})\frac{\rho L}{\frac{2}{3}S_1}\] \[=(\frac{3}{4})\frac{I_1 \rho L}{S_1}\] \[=\frac{3}{8}e_1\] \[37.5[\%]\] | \[Q_2=2I^2_2R_2\] \[=2(\frac{I_1}{2})^2\frac{\rho L}{S_2}\] \[=(\frac{I_1^2}{2})\frac{\rho L}{\frac{2}{3}S_1}\] \[=(\frac{3}{4})\frac{I_1^2 \rho L}{S_1}\] \[=\frac{3}{8}Q_1\] \[37.5\%\] | |
3상3선식 | \[P=\sqrt3 EI_3\] \[V=3S_3L\] | \[I_3=\frac{I_1}{\sqrt3}\] \[57.7[\%]\] | \[S_3=\frac{2}{3}S_1\] \[66.7[\%]\] | \[e_3=\sqrt 3I_3R_3\] \[=\sqrt3(\frac{I_1}{\sqrt3})\frac{\rho L}{S_3}\] \[=I_1\frac{\rho L}{\frac{2}{3}S_1}\] \[=(\frac{3}{2})\frac{I_1 \rho L}{S_1}\] \[=\frac{3}{4}e_1\] \[75[\%]\] | \[Q_3=3I^2_3R_3\] \[=3(\frac{I_1}{\sqrt3})^2\frac{\rho L}{S_3}\] \[=I_1^2\frac{\rho L}{\frac{2}{3}S_1}\] \[=(\frac{3}{2})\frac{I_1^2 \rho L}{S_1}\] \[=\frac{3}{4}Q_1\] \[75\%\] | |
3상4선식 | \[P=3EI_4\] \[V=4S_4L\] | \[I_4=\frac{I_1}{3}\] \[33.3[\%]\] | \[S_4=\frac{1}{2}S_1\] \[50[\%]\] | \[e_4=I_4R_4\] \[=(\frac{I_1}{3})\frac{\rho L}{S_4}\] \[=(\frac{I_1}{3})\frac{\rho L}{\frac{2}{1}S_1}\] \[=(\frac{3}{3})\frac{I_1 \rho L}{S_1}\] \[=\frac{1}{3}e_1\] \[33.3[\%]\] | \[Q_4=3I^2_4R_4\] \[=3(\frac{I_1}{3})^2\frac{\rho L}{S_4}\] \[=(\frac{I_1^2}{3})\frac{\rho L}{\frac{1}{2}S_1}\] \[=(\frac{2}{3})\frac{I_1^2 \rho L}{S_1}\] \[=\frac{1}{3}Q_1\] \[33.3\%\] |
1️⃣단상2선식
- 결선도
- 공급전력 전선총량
\[P=EI_1\]
\[V=2S_1L\]
- 선전류
\[I_1\]
\[100[\%]\]
- 전선단면적
\[S_1\]
\[100[\%]\]
- 전압강하
\[e_1=2I_1R_1\]
\[=2\frac{I_1\rho L}{S_1}\]
\[100[\%]\]
- 배전손실
\[Q_1=2I^2_1R_1\]
\[=2I^2_1\frac{\rho L}{S_1}\]
\[100\%\]
2️⃣단상3선식
- 결선도
- 공급전력 전선총량
\[P=2EI_2\]
\[V=3S_2L\]
- 선전류
\[I_2=\frac{I_1}{2}\]
\[50[\%]\]
- 전선단면적
\[S_2=\frac{2}{3} S_1\]
\[66.7[\%]\]
- 전압강하
\[e_2=I_2R_2\]
\[=(\frac{I_1}{2})\frac{\rho L}{S_2}\]
\[=(\frac{I_1}{2})\frac{\rho L}{\frac{2}{3}S_1}\]
\[=(\frac{3}{4})\frac{I_1 \rho L}{S_1}\]
\[=\frac{3}{8}e_1\]
\[37.5[\%]\]
- 배전손실
\[Q_2=2I^2_2R_2\]
\[=2(\frac{I_1}{2})^2\frac{\rho L}{S_2}\]
\[=(\frac{I_1^2}{2})\frac{\rho L}{\frac{2}{3}S_1}\]
\[=(\frac{3}{4})\frac{I_1^2 \rho L}{S_1}\]
\[=\frac{3}{8}Q_1\]
\[37.5\%\]
3️⃣3상3선식
- 결선도
- 공급전력 전선총량
\[P=\sqrt3 EI_3\]
\[V=3S_3L\]
- 선전류
\[I_3=\frac{I_1}{\sqrt3}\]
\[57.7[\%]\]
- 전선단면적
\[S_3=\frac{2}{3}S_1\]
\[66.7[\%]\]
- 전압강하
\[e_3=\sqrt 3I_3R_3\]
\[=\sqrt3(\frac{I_1}{\sqrt3})\frac{\rho L}{S_3}\]
\[=I_1\frac{\rho L}{\frac{2}{3}S_1}\]
\[=(\frac{3}{2})\frac{I_1 \rho L}{S_1}\]
\[=\frac{3}{4}e_1\]
\[75[\%]\]
- 배전손실
\[Q_3=3I^2_3R_3\]
\[=3(\frac{I_1}{\sqrt3})^2\frac{\rho L}{S_3}\]
\[=I_1^2\frac{\rho L}{\frac{2}{3}S_1}\]
\[=(\frac{3}{2})\frac{I_1^2 \rho L}{S_1}\]
\[=\frac{3}{4}Q_1\]
\[75\%\]
4️⃣3상4선식
- 결선도
- 공급전력 전선총량
\[P=3EI_4\]
\[V=4S_4L\]
- 선전류
\[I_4=\frac{I_1}{3}\]
\[33.3[\%]\]
- 전선단면적
\[S_4=\frac{1}{2}S_1\]
\[50[\%]\]
- 전압강하
\[e_4=I_4R_4\]
\[=(\frac{I_1}{3})\frac{\rho L}{S_4}\]
\[=(\frac{I_1}{3})\frac{\rho L}{\frac{2}{1}S_1}\]
\[=(\frac{3}{3})\frac{I_1 \rho L}{S_1}\]
\[=\frac{1}{3}e_1\]
\[33.3[\%]\]
- 배전손실
\[Q_4=3I^2_4R_4\]
\[=3(\frac{I_1}{3})^2\frac{\rho L}{S_4}\]
\[=(\frac{I_1^2}{3})\frac{\rho L}{\frac{1}{2}S_1}\]
\[=(\frac{2}{3})\frac{I_1^2 \rho L}{S_1}\]
\[=\frac{1}{3}Q_1\]
\[33.3\%\]
목차(저압 옥내배전방식)
저압 옥내배전방식
💯기출문제
●A1.저압옥내배전방식에 대하여 설명하시오 (133)
🌐V1015P24
답글 남기기